Mathematics: Compiled from the Best Authors, and Intended to be the Text-book of the Course of Private Lectures on These Sciences in the University at Cambridge, Band 1W. Hilliard, 1808 |
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Seite 35
... gallon of train oil A firkin of soap 64 A faggot of steel A barrel of pot - ashes ... 200 A stone of glass A barrel of anchovies .... 30 A seam of glass is 24 stone , lb. ..... 7 호 120 5 120 lb. oz . dr . weighs ..... 17 6 1 14 A half ...
... gallon of train oil A firkin of soap 64 A faggot of steel A barrel of pot - ashes ... 200 A stone of glass A barrel of anchovies .... 30 A seam of glass is 24 stone , lb. ..... 7 호 120 5 120 lb. oz . dr . weighs ..... 17 6 1 14 A half ...
Seite 36
... gallon gal . 2 kilderkins 1 barrel bar . 8 gallons 1 firkin of Ale fir . [ 3 kilderkins 1 hogshead hhd . 9 gallons 1 firkin of Beer fir . 13 barrels 1 butt butt . NOTE . The ale gallon contains 282 cubic inches . In London the ale ...
... gallon gal . 2 kilderkins 1 barrel bar . 8 gallons 1 firkin of Ale fir . [ 3 kilderkins 1 hogshead hhd . 9 gallons 1 firkin of Beer fir . 13 barrels 1 butt butt . NOTE . The ale gallon contains 282 cubic inches . In London the ale ...
Seite 37
... gallons 1 gallon 1 tierce gal . tier . 2 pipes butt 63 gallons 1 hogshead hhd . 18 gallons 84 gallons 1 puncheon pun . 31 gallons 1 tun Marked p . or b . T. 1 runlet rund . 1 barrel bar . By this measure , brandy , spirits , perry ...
... gallons 1 gallon 1 tierce gal . tier . 2 pipes butt 63 gallons 1 hogshead hhd . 18 gallons 84 gallons 1 puncheon pun . 31 gallons 1 tun Marked p . or b . T. 1 runlet rund . 1 barrel bar . By this measure , brandy , spirits , perry ...
Seite 46
... gallons of brandy , at 9s . 6d . per gallon . Ans . 51. 14s . CASE 1 . If the multiplier exceed 12 , multiply succesively by its com- ponent parts , instead of the whole number at once , as in sim- ple multiplication . EXAMPLES . 1 ...
... gallons of brandy , at 9s . 6d . per gallon . Ans . 51. 14s . CASE 1 . If the multiplier exceed 12 , multiply succesively by its com- ponent parts , instead of the whole number at once , as in sim- ple multiplication . EXAMPLES . 1 ...
Seite 108
... gallon ? Ans . 20 gallons . 31. If 15 ells of stuff , will 40 ells of the same stuff cost , being yard wide ? yard wide , cost 37s . 6d . what Ans . 61. 13s . 4d . 32. Shipped for Barbadoes 500 pairs of stockings at 3s . 6d . per pair ...
... gallon ? Ans . 20 gallons . 31. If 15 ells of stuff , will 40 ells of the same stuff cost , being yard wide ? yard wide , cost 37s . 6d . what Ans . 61. 13s . 4d . 32. Shipped for Barbadoes 500 pairs of stockings at 3s . 6d . per pair ...
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affirmative amount of 11 angle annuity annum arithmetical Bisect carats cent centre chord circle circumference coefficient common denominator completing the square compound interest compound quantity consequently cube root debt decimal denoted diameter difference Divide dividend division divisor draw equal equation EXAMPLES exponent figure fourth gallons geometrical progression geometrical series give given number greater greatest common measure half improper fraction infinite series less number logarithm manner Multiply negative NOTE nth root number of combinations number of terms number of things payment perpendicular polygon present worth PROBLEM proportion quadratic equation quotient radius ratio Reduce remainder repetend required to find right line RULE sides simple interest sine square root subtract Suppose surd taken tangent third unknown quantity vulgar fraction Whence whole number yards
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Seite 175 - RULE.* — Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the true time required.
Seite 140 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Seite 255 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Seite 198 - A man was hired 50 days on these conditions. — that, for every day he worked, he should receive $ '75, and, for every day he was idle, he should forfeit $ '25 ; at the expiration of the time, he received $ 27'50 ; how many days did he work...
Seite 149 - To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply it by the number denoting the given power, for a divisor.
Seite 315 - If A and B together can perform a piece of work in 8 days, A and C together in 9 days, and B and C in 10 days : how many days would it take each person to perform the same work alone ? Ans.
Seite 124 - As the sum of the several products, Is to the whole gain or loss ; So is each man's particular product, To his particular share of the gain or loss.
Seite 139 - ... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Seite 120 - When it is required to find how many of the first sort of coin, weight or measure, mentioned in the question, are equal to a given quantity of the last.
Seite 132 - When one of the ingredients is limited to a certain quantity. RULE. Take the difference between each price and the mean rate, as before ; then,