Mathematics: Compiled from the Best Authors, and Intended to be the Text-book of the Course of Private Lectures on These Sciences in the University at Cambridge, Band 1W. Hilliard, 1808 |
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Seite 53
... common measure of two or more numbers is that number , which will divide each of them without a remain- der . Thus 3 is the common measure of 12 and 15 ; and the greatest number , that will do this , is called the greatest common ...
... common measure of two or more numbers is that number , which will divide each of them without a remain- der . Thus 3 is the common measure of 12 and 15 ; and the greatest number , that will do this , is called the greatest common ...
Seite 54
... common multiple ; thus 30 , 45 , 60 , and 75 , are multi- ples of 3 and 5 ; but their least common multiple is 15. * PROBLEM I. To find the greatest common measure of two or more numbers . RULE.t 1. If there be two numbers only , divide ...
... common multiple ; thus 30 , 45 , 60 , and 75 , are multi- ples of 3 and 5 ; but their least common multiple is 15. * PROBLEM I. To find the greatest common measure of two or more numbers . RULE.t 1. If there be two numbers only , divide ...
Seite 55
... divisor by the last remain- der ; then will the last divisor be the greatest common measure required . 2. When there are more than two numbers , find the great- est common measure of two of them as before ; and of that common measure ...
... divisor by the last remain- der ; then will the last divisor be the greatest common measure required . 2. When there are more than two numbers , find the great- est common measure of two of them as before ; and of that common measure ...
Seite 56
... greatest common measure ; and the quotient will be their least common multiple . 2. When there are more than two numbers , find the least common multiple of two of them as before ; and of that com- mon multiple and one of the other ...
... greatest common measure ; and the quotient will be their least common multiple . 2. When there are more than two numbers , find the least common multiple of two of them as before ; and of that com- mon multiple and one of the other ...
Seite 58
... greatest common measure , and the quotients will be the terms of the fraction required . EXAMPLES : 1. Reduce to its lowest terms . ( 2 ) ( 2 ) ( 3 ) ( 2 ) ( 2 ) 1447230 240-120 0 Or thus : 144 ) 240 ( 1 144 96 ) 144 ( 1 96 48 ) 96 ( 2 ...
... greatest common measure , and the quotients will be the terms of the fraction required . EXAMPLES : 1. Reduce to its lowest terms . ( 2 ) ( 2 ) ( 3 ) ( 2 ) ( 2 ) 1447230 240-120 0 Or thus : 144 ) 240 ( 1 144 96 ) 144 ( 1 96 48 ) 96 ( 2 ...
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Häufige Begriffe und Wortgruppen
affirmative amount of 11 angle annuity annum arithmetical Bisect carats cent centre chord circle circumference coefficient common denominator completing the square compound interest compound quantity consequently cube root debt decimal denoted diameter difference Divide dividend division divisor draw equal equation EXAMPLES exponent figure fourth gallons geometrical progression geometrical series give given number greater greatest common measure half improper fraction infinite series less number logarithm manner Multiply negative NOTE nth root number of combinations number of terms number of things payment perpendicular polygon present worth PROBLEM proportion quadratic equation quotient radius ratio Reduce remainder repetend required to find right line RULE sides simple interest sine square root subtract Suppose surd taken tangent third unknown quantity vulgar fraction Whence whole number yards
Beliebte Passagen
Seite 175 - RULE.* — Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the true time required.
Seite 140 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Seite 255 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Seite 198 - A man was hired 50 days on these conditions. — that, for every day he worked, he should receive $ '75, and, for every day he was idle, he should forfeit $ '25 ; at the expiration of the time, he received $ 27'50 ; how many days did he work...
Seite 149 - To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply it by the number denoting the given power, for a divisor.
Seite 315 - If A and B together can perform a piece of work in 8 days, A and C together in 9 days, and B and C in 10 days : how many days would it take each person to perform the same work alone ? Ans.
Seite 124 - As the sum of the several products, Is to the whole gain or loss ; So is each man's particular product, To his particular share of the gain or loss.
Seite 139 - ... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Seite 120 - When it is required to find how many of the first sort of coin, weight or measure, mentioned in the question, are equal to a given quantity of the last.
Seite 132 - When one of the ingredients is limited to a certain quantity. RULE. Take the difference between each price and the mean rate, as before ; then,