 | 1801 - 446 Seiten
...; what had he at first ? Ans. 2os. 21. To divide the number 90 into 4 such parts, that if the first be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2t" the sum, difference, product, and quotient, shall be all equal to each other. Ans. The parts are... | |
 | Bewick Bridge - 1818 - 254 Seiten
...inverted. What is the number ? ANSW. 53. Qu. 33. Divide the number 90 into four such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, may all be equal to the same quantity. ANSW. 18, 22, 10, 40. Qu. 34. A merchant has two kinds often,... | |
 | Adrien Marie Legendre - 1819 - 574 Seiten
...value triple that of the first : what is the value of each horse ? Ans. one 30l. and the other 402. 64. To divide the number 90 into four such parts that if the first be increased by Z, the second diminished by 2, the third multiplied by 2, and the fourth divided by... | |
 | Bewick Bridge - 1821 - 648 Seiten
...inverted. What is the number ? ANSW. 53. Qu. 33. Divide the number 90 into four such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, may all be equal to the same quantity. ANSW. 18,22,10,40. Qu. 34. A merchant has two kinds of tea,... | |
 | 1825 - 490 Seiten
...-(- 12 won. lost. remaining. or, 12 x = 12, and x = 1 ; Therefore, 28 x = 28«. money at first. 2. It is required to divide the number 90 into four such parts, that if the first be increased by 2 ; the second diminished by 2; the third multiplied by 2; and the fourth divided by... | |
 | Silvestre François Lacroix - 1825 - 294 Seiten
...value triple that of the first : what is the value of each horse Ans. one 301. and the other 401. 64. To divide the number 90 into four such parts that if the first be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by... | |
 | Warren Colburn - 1825 - 400 Seiten
...as many as both ol you will have left. How many had each ? 5. It is required to divide the number 72 into four such parts, that if the first part be increased by 5, the second part diminished by 5, the third part multiplied by 5, and the fourth part divided by... | |
 | Jeremiah Day - 1827 - 352 Seiten
...each horse ? Ans. 56 and 33 guineas. Prob. 30. Divide the number 90 into 4 such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall all be equal. If x, y, and z, be three of the parts, the fourth will be 90 — x—y — z. And... | |
 | Warren Colburn - 1828 - 330 Seiten
...as many as both of you will have left. How many had each ? 5. It is required to divide the number 72 into four such parts, that if the first part be increased by 5, the second part diminished by 5, the third part multiplied by 5, and the fourth part divided by... | |
 | John Bonnycastle - 1829 - 372 Seiten
...much as 3 of the hare's ; how many leaps must the greyhound take to catch the hare ? Ans. 300. J2. It is required to divide the number 90 into four such...the second diminished by 2, the third multiplied by i?, and tht fourth divided by 2, the sum, difference, product, and quotient, shall be all equal ? Ans.... | |
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Divide the number 90 into 4 such parts, that the . first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall all be equal. 
