 | Miles Bland - 1819 - 442 Seiten
...base, and the lines joining the intersections of the sides and the angles opposite, will be equal. 11. If from any point in the base of an isosceles...either extremity of the base to the opposite side. 12. Of all triangles having the same vertical angle, and whose bases -pass through a given point, the... | |
 | Andrew Bell - 1837 - 290 Seiten
...vertical angle, is equal to half the difference of the angles at the base. 17- If from any point hi the base of an isosceles triangle perpendiculars be drawn to the sides, their sum will be equal to the perpendicular from either extremity of the base upon the opposite side... | |
 | University of Sydney - 1853 - 134 Seiten
...the one to one side of the other, shew that the triangles are equal, without assuming Prop. 47, BI 5. If from any point in the base of an isosceles triangle perpendiculars be let fall upon the equal sides, shew that the sum of these perpendiculars is independent of the position... | |
 | Euclides - 1860 - 142 Seiten
...therefore angle DCO = FCO ; that is, the vertical angle C is bisected. EXERCISE XXVI. — THEOREM. If from any point in the base of an isosceles triangle perpendiculars be drawn to the sides, their sum will be equal to the perpendicular from either extremity of the base upon the opposite side.... | |
 | Richard Wormell - 1868 - 286 Seiten
...distance of the first from the second is half that from the second to the third. 31. If from points in the base of an isosceles triangle perpendiculars be drawn to the sides, their sum is the same for each of the points. 32. Construct a parallelogram having given, — 1st.... | |
 | Richard Wormell - 1870 - 304 Seiten
...distance of the first from the second is half that from the second to the third. 31. If from points in the base of an isosceles triangle perpendiculars be drawn to the sides, their sum is the same for each of the points. 32. Construct a parallelogram having given, — 1st.... | |
 | Edward Olney - 1872 - 96 Seiten
...formed whose perimeter is constant and equal to the sum of the two equal sides of the triangle. 660. If from any point in the base of an isosceles triangle perpendiculars be drawn to the sides of the triangle, their sum is constant and equal to the perpendicular from one of the equal angles... | |
 | Edward Olney - 1872 - 562 Seiten
...formed whose perimeter is constant and equal to the sum of the two equal sides of the triangle. 660. If from any point in the base of an isosceles triangle perpendiculars be drawn to the sides of the triangle, their sum is constant and equal to the perpendicular from one of the equal angles... | |
 | Edward Olney - 1872 - 102 Seiten
...perimeter is constant and equal to the sum of the two equal sides of the triangle. Fio. 3fi6. 660. If from any point in the base of an isosceles triangle perpendiculars be drawn to the sides of the triangle, their sum is constant and equal to the perpendicular from one of the equal angles... | |
 | Richard Wormell - 1876 - 268 Seiten
...of two sides of a triangle is equal to half the third side and is parallel to it. 44. If from points in the base of an isosceles triangle perpendiculars be drawn to the sides, their sum is the sa.me for each of the points. 45. The straight lines joining the middle points of... | |
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If from any point in the base of an isosceles triangle perpendiculars... 
