An Encyclopædia of Architecture: Historical, Theoretical, and PracticalLongman, Brown, Green, and Longmans, 1842 - 1089 Seiten |
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Seite 294
... inches and parts equivalent to 5417 of a foot . that a foot contains 12 inches , we have - Remembering 5417 12 6.5004 inches ; and 1 inch consisting of 12 parts 6.0048 parts ; hence 5417 is equal to 6 inches , and 6'0048 parts . Again ...
... inches and parts equivalent to 5417 of a foot . that a foot contains 12 inches , we have - Remembering 5417 12 6.5004 inches ; and 1 inch consisting of 12 parts 6.0048 parts ; hence 5417 is equal to 6 inches , and 6'0048 parts . Again ...
Seite 297
... inches under inches , and multiply each term in the multiplicand by the feet in the multiplier , beginning at the lowest ; and , if the numbers be large , put down the inches without carrying 1 for every 12 from inches to feet . Then ...
... inches under inches , and multiply each term in the multiplicand by the feet in the multiplier , beginning at the lowest ; and , if the numbers be large , put down the inches without carrying 1 for every 12 from inches to feet . Then ...
Seite 378
... inches , feet , yards , & c . said to be of so many cubic inches , feet , yards , & c . or another of equal magnitude . Solids are measured by units which Whence the solidity of a body is as will occupy its capacity or space , - 1230 ...
... inches , feet , yards , & c . said to be of so many cubic inches , feet , yards , & c . or another of equal magnitude . Solids are measured by units which Whence the solidity of a body is as will occupy its capacity or space , - 1230 ...
Seite 379
... inches . Here , 3 feet 4 inches x 4-13 feet 4 inches , and 2 feet 2 inches x 48 feet 8 inches ; and 13 feet 4 inches + 8 feet 8 inches = 22 . Then 22 ÷ 2 x 10-110 feet , the surface required . Example 2. Required the convex surface of ...
... inches . Here , 3 feet 4 inches x 4-13 feet 4 inches , and 2 feet 2 inches x 48 feet 8 inches ; and 13 feet 4 inches + 8 feet 8 inches = 22 . Then 22 ÷ 2 x 10-110 feet , the surface required . Example 2. Required the convex surface of ...
Seite 380
... inches , and those of the lesser ends 6 inches , and its altitude 24 feet . Here , 5 x 5 = 25 , area of the lesser end , and 1 · 25 × 1 · 25 = 1 · 5625 , area of the greater end : The mean proportional therefore √25 × 1 · 5625 = ' 625 ...
... inches , and those of the lesser ends 6 inches , and its altitude 24 feet . Here , 5 x 5 = 25 , area of the lesser end , and 1 · 25 × 1 · 25 = 1 · 5625 , area of the greater end : The mean proportional therefore √25 × 1 · 5625 = ' 625 ...
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1-inch deal 15th century arch architect architecture architrave axis balusters base bead butt bead flush breadth bricks building called cathedral centre of gravity century church circle circular circumference colour columns construction Corinthian order cube cubic foot curve cutting described diameter divided divisor Doric order draw edge edifices ellipsis entablature equal equation erected example extrados feet foot fraction half height Hence horizontal inches intercolumniations iron joints length lime limestone moulded multiplied nave oolite ornaments ovolo palace panels parallel parallelogram perpendicular piece piers placed plane portico Prop proportion pyramid quantity radius rectangle right angles right line Roman Roman architecture roof sandstone scantlings side sofite solid square root stone style subtract supposed surface tangent temple thickness timber tower transepts triangle vault vertical Vitruvius voussoirs wainscot walls whence whereof width