Elements of Geometry and Plane Trigonometry: With an Appendix, and Copious Notes and IllustrationsA. Constable & Company, 1817 - 432 Seiten |
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Seite 16
... bisect . In the side AB take any point D , and from BC cut off BE equal to BD ; join DE , on which construct ( I. 1 ... bisects it must be the per- pendicular required . Taking BD , therefore , equal to BE , and F B constructing the ...
... bisect . In the side AB take any point D , and from BC cut off BE equal to BD ; join DE , on which construct ( I. 1 ... bisects it must be the per- pendicular required . Taking BD , therefore , equal to BE , and F B constructing the ...
Seite 17
... be equal ; these subordinate triangles are ( I. 3. ) equal , and consequently the angle DGC is equal to DGF , and each of them a right angle , or CG is per- pendicular to AB . PROP . VII . PROB . To bisect a given BOOK I. 17.
... be equal ; these subordinate triangles are ( I. 3. ) equal , and consequently the angle DGC is equal to DGF , and each of them a right angle , or CG is per- pendicular to AB . PROP . VII . PROB . To bisect a given BOOK I. 17.
Seite 18
... bisect a given finite straight line . On the given straight line AB , construct two isosceles triangles ( I. 1. ) ACB and ADB , and join their vertices C and D by a straight line cutting AB in the point E : AB is bisected in E. E B For ...
... bisect a given finite straight line . On the given straight line AB , construct two isosceles triangles ( I. 1. ) ACB and ADB , and join their vertices C and D by a straight line cutting AB in the point E : AB is bisected in E. E B For ...
Seite 20
... bisecting the vertical angle ABC . Because , by hypothesis , AB is equal to BC , the side BD common to the two tri- angles BDA and BDC , and the angles ABD and CBD contained by them are equal ; these triangles are equal ( I. 3. ) , and ...
... bisecting the vertical angle ABC . Because , by hypothesis , AB is equal to BC , the side BD common to the two tri- angles BDA and BDC , and the angles ABD and CBD contained by them are equal ; these triangles are equal ( I. 3. ) , and ...
Seite 48
... bisects the rhomboid DEFC ( I. 26. cor . ) , and the triangles DBC and DEC , having A the same altitude , are equivalent ( II . 1. ) ; consequently their doubles , or the triangle ABC and the ... bisect the base 48 FLEMENTS OF GEOMETRY .
... bisects the rhomboid DEFC ( I. 26. cor . ) , and the triangles DBC and DEC , having A the same altitude , are equivalent ( II . 1. ) ; consequently their doubles , or the triangle ABC and the ... bisect the base 48 FLEMENTS OF GEOMETRY .
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Elements of Geometry, and Plane Trigonometry: With an Appendix, and Very ... University Professor Emeritus John Leslie, Sir Keine Leseprobe verfügbar - 2016 |
Häufige Begriffe und Wortgruppen
ABCD adjacent angle altitude angle ABC angle ADB angle BAC base AC bisect centre chord circle circumference consequently construction contained angle cosine decagon denote describe diameter difference distance diverging lines divided draw equal to BC equilateral triangle equivalent to twice evidently exterior angle given greater half Hence hypotenuse inscribed isosceles triangle join let fall likewise measure parallel perpendicular point G polygon PROB PROP Proposition quadrilateral figure quantities radius ratio rectangle rectangle contained rectilineal figure rhomboid right angles right-angled triangle Scholium segments semicircle semiperimeter sequently side AC sinB sine square of AB square of AC straight line tangent THEOR tion triangle ABC twice the rectangle twice the square vertex vertical angle whence Wherefore