Elements of Geometry and Plane Trigonometry: With an Appendix, and Copious Notes and IllustrationsA. Constable & Company, 1817 - 432 Seiten |
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Seite 12
... H be equal to each other , the triangle will evidently be isosceles ; and if those lines be likewise equal to the base AB , the triangle must be equi lateral . PROP . II . THEOREM . Two triangles are equal 12 ELEMENTS OF GEOMETRY .
... H be equal to each other , the triangle will evidently be isosceles ; and if those lines be likewise equal to the base AB , the triangle must be equi lateral . PROP . II . THEOREM . Two triangles are equal 12 ELEMENTS OF GEOMETRY .
Seite 19
... evidently greater than DCE ; it is con- sequently greater than DBA or CBA . qr In like manner , it may be shown , that if BC be produ- ced , the exterior angle ACG is greater than CAB . But ' ACG is equal to the vertical angle BCF , and ...
... evidently greater than DCE ; it is con- sequently greater than DBA or CBA . qr In like manner , it may be shown , that if BC be produ- ced , the exterior angle ACG is greater than CAB . But ' ACG is equal to the vertical angle BCF , and ...
Seite 21
... evidently greater than DAB ; but since BA is equal to BD , this angle DAB ( I. 10. ) is equal to ADB , and consequently CAB is greater than ADB . Again , the angle ADB , being an exte- rior angle of the triangle CAD , is ( I. 8 ...
... evidently greater than DAB ; but since BA is equal to BD , this angle DAB ( I. 10. ) is equal to ADB , and consequently CAB is greater than ADB . Again , the angle ADB , being an exte- rior angle of the triangle CAD , is ( I. 8 ...
Seite 26
... evidently isosceles , its angles BGC and BCG ( I. 10. ) are equal . Whence the angle AGC , being greater than BGC or BCG , which a- gain is greater than ACG , must be still greater than ACG ; and therefore the opposite side AC is ( I ...
... evidently isosceles , its angles BGC and BCG ( I. 10. ) are equal . Whence the angle AGC , being greater than BGC or BCG , which a- gain is greater than ACG , must be still greater than ACG ; and therefore the opposite side AC is ( I ...
Seite 31
... evidently encounter the single intermediate limit of equality . Wherefore , there is a certain position CD , in which the line revolving about the point F makes the ex- terior angle EFC equal to the interior EGA , and at the same ...
... evidently encounter the single intermediate limit of equality . Wherefore , there is a certain position CD , in which the line revolving about the point F makes the ex- terior angle EFC equal to the interior EGA , and at the same ...
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Elements of Geometry, and Plane Trigonometry: With an Appendix, and Very ... University Professor Emeritus John Leslie, Sir Keine Leseprobe verfügbar - 2016 |
Häufige Begriffe und Wortgruppen
ABCD adjacent angle altitude angle ABC angle ADB angle BAC base AC bisect centre chord circle circumference consequently construction contained angle cosine decagon denote describe diameter difference distance diverging lines divided draw equal to BC equilateral triangle equivalent to twice evidently exterior angle given greater half Hence hypotenuse inscribed isosceles triangle join let fall likewise measure parallel perpendicular point G polygon PROB PROP Proposition quadrilateral figure quantities radius ratio rectangle rectangle contained rectilineal figure rhomboid right angles right-angled triangle Scholium segments semicircle semiperimeter sequently side AC sinB sine square of AB square of AC straight line tangent THEOR tion triangle ABC twice the rectangle twice the square vertex vertical angle whence Wherefore