 | Charles Hutton - 1807 - 464 Seiten
...Ex. 4. To find the area of a circle whose circumference is 12 feet. Ans. 11-4595 PROBLEM X. To And the Area of a Circular Ring, or of the Space included between the Circumferences of two Circles i the one being contained within the other. TAKE the difference between... | |
 | Charles Hutton - 1812 - 620 Seiten
...1-069. Ex. 4. To find the area of a circje whose circumference is 12 feet. Ans. 11-4595, PROBLEM X. To. find the Area of a Circular Ring, or of the Space included between the Circumferences of two Circles ; the one being contained within the other. TAKE the difference between... | |
 | Thomas Keith - 1817 - 306 Seiten
...Prob. XVI.) area of the trapezium = 547'4, area of the whole compound figure = 632'673'26. PROBLEM XIX. To find the Area of a circular Ring, or of the Space indudtd betwtcn two concentric Circles. RULE*. Muliiply the sum of the diameters of the two circles... | |
 | Robert Brunton - 1828 - 222 Seiten
...the reciprocal of 12.5664 is .07958, or -5 = C .07958; hence the rule c2 X .07958 = area. PROBLEM X. To find the area of a circular Ring, or of the space included bet-ween the circumferences of two circles; the one being contained -within the other. RULE. Take the difference... | |
 | Charles Hutton - 1831 - 660 Seiten
...1-069. Ex. 4. To find the area of a circle, whose circumference is 12 feet. Ans. 11-1595. PROBLEM X. To find the Area of a Circular Ring, or of the Space included betteten the Circumferences of two Circles ; fhe*one being contained ipiihin the other. TAKE the difference... | |
 | Ireland commissioners of nat. educ - 1834 - 370 Seiten
...Ans. 395-4369. 4. Let AB = 96, С D = 60, and their distance 26 : required the area ? Ans. 2138-7527. PROBLEM XXX. To find the area of a circular ring,...the space included between two concentric circles. RULE. Multiply the sum of the two diameters by their difference and the product arising by -7854 for... | |
 | Commissioners of National Education in Ireland - 1837 - 290 Seiten
...96, CD - 60, and their distance = 26; required the area ? Ans. 2136-7527. MENSURATION OF SUPERFICIES. PROBLEM XXX. To find the area of a circular ring,...the space included between two concentric circles. RULE. Multiply the sum of the two diameters by their difference, and the product arising by -7854 for... | |
 | Thomas Hunter - 1878 - 142 Seiten
...How many square feet are there in a circle whose circumference is 10.9956? Ans. 86.5933. PROBLEM XII. To find the area of a circular ring, or of the space included between * Rule I—In this rale the circumference is made np of an infinite number of straight lines, each... | |
 | 1894 - 330 Seiten
...circumference 314-16. By (i) — 314-16 By (2) — 10o2 = 10000 10o -7854 Area 7854^ 7854 Area. PROB. XII. — To find the area of a circular ring, or of the space included between two concentric circles. Multiply the sum of the two diameters by their difference, and this product by -7854. Example. —... | |
 | Thomas Aloysius O'Donahue - 1896 - 186 Seiten
...circumference 314-16. By (1) — 314-16 By (2) — 1002= 10,000 „.__, . 7854 Area. 7854 Area. PBOB. XII. To find the area of a circular ring, or of the space included between two concentric circles. Multiply the sum of the two diameters by their difference, and this product by -7854. Let there be... | |
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To find the area of a circle, whose diameter is 7, and circumference 22. Ans. 