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according added Algebra answer Arithmetic arranged called Change co-efficient commencing common denominator common ratio complete compound quantity consequently consist containing course cube DEFINITIONS denominator difference Divide dividend divisor double equal equation EXAMPLE EXERCISES IN CHAPTER exponent expressed Extracting factors fifth former four fourth fraction geometrical progression give given quantity greater greatest common measure half Hence hour integer known least common multiple less letters means merely Method miles mixed Multiply necessary NOTE object obtain operations positive Practical preceded PROBLEM proportion Quadratic question quotient Raise Reduce regard remainder represent resolved resulting RULE separately shillings side simple Quantity smaller sometimes square root subtract taken term THEOREM third tion twice unknown quantity usual vinculum volume whole number write
Seite 36 - The first and fourth terms of a proportion are called the extremes, and the second and third terms, the means. Thus, in the foregoing proportion, 8 and 3 are the extremes and 4 and 6 are the means.
Seite 36 - THEOREM. lf the first has to the second the same ratio which the third has to the fourth, but the third to the fourth, a greater ratio than the fifth has to the sixth ; the first shall also have to the second a greater ratio than the fifth, has to the sixth.
Seite 64 - Proportion, when the ratio is the same between every two adjacent terms, viz. when the first is to the second, as the second to the third, as the third to the fourth, as the fourth to the fifth, and so on, all in the same common ratio.
Seite 19 - Divide the greater number by the less, the divisor by the remainder, and thus continue to divide the last divisor by the last remainder until there is no remainder ; the last divisor will be the greatest common divisor.
Seite 36 - If the product of two quantities be equal to the product of two others, two of them may be made the extremes and the other two the means of a proportion.
Seite 31 - Reduce the mixed numbers to improper fractions, and compound fractions to simple ones ; after this has been done, multiply all the numerators together for the numerator of the product, and all the denominators together for its denominator. Multiply 6| by | of |. Here the mixed number 6§ _ ,p and | of J = H 6* is converted into the " " improper fraction «, and then ¥' X « = \V
Seite 84 - ... To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part.
Seite 48 - To divide the number 90 into four such parts, that if the first be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the sum, difference, product, and quotient so obtained, will be all equal to each other.