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" Angles, taken together, is equal to Twice as many Right Angles, wanting four, as the Figure has Sides. "
Popular Mathematics: Being the First Elements of Arithmetic, Algebra, and ... - Seite 259
von Robert Mudie - 1836 - 496 Seiten
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A Royal Road to Geometry: Or, an Easy and Familiar Introduction to the ...

Thomas Malton - 1774 - 484 Seiten
...bered amongft the other Theorems. THEO. i. All the internal Angles, of every right lined FiV gure, are equal to twice as many Right Angles, wanting four, as the Figure has Sides. , Every right lined Figure, may be refolved into as many Triangles, as the Figure has Sides, wanting...
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A Course of Mathematics ...: Designed for the Use of the Officers ..., Band 1

Isaac Dalby - 1807 - 476 Seiten
...right angles (41), constitute the interior angles of the polygon, and therefore those angles together are equal to twice as many right angles, wanting four, as the po» lyeon has sides. 44. The sum of tf-^-xterior angles (aAG, IEA, &c.) of any polygon, are equal...
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The Modern Preceptor ; Or, a General Course of Education, Band 1

John Dougall - 1810 - 734 Seiten
...thirds of one right angle. Puop. VIII. fig. 91. The sum of all the interior angles of a polygon is equal to twice as many right angles, wanting four, as the figure has sides. Let the figure ABCDEF, be a polygon of six sides, that is, a hexagon. From any point within it, as...
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A Course of Mathematics ...: Composed for the Use of the Royal Military ...

Charles Hutton - 1811 - 406 Seiten
...right angles. THEOREM XIX. IN any figure whatever, the Sum of all the Inward Angles, taken together, is equal to Twice as many Right Angles, wanting four, as the Figure has Sides. Let ABCDE be any figure ; then the sum of all its inward angles, A + B + c + D + E, is equal to twice...
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A Course of Mathematics: For the Use of Academies as Well as Private Tuition

Charles Hutton - 1812 - 620 Seiten
...angles. THEOREM XIX. IN any figure whatever, the Sum of all the Inward Arfgles, taken together, is equal to Twice as many Right Angles, wanting four, as the Figure has Sides. Let ABCHE be any figure ; then the sum of all its inward angles, A -f- B -f. c + D + E, is equal to...
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Easy Introduction to Mathematics, Band 2

Charles Butler - 1814 - 582 Seiten
...thus, since it follows from prop. 32. book 1. of Euclid, that all the interior angles (taken together) of every rectilineal figure are equal to twice as...right angles, wanting four, as the figure has sides, the same thing must be true of each particular kind of such figure ; as of squares, triangles, trapeziums,...
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A Course of Mathematics: For the Use of Academies, as Well as Private ...

Charles Hutton - 1822 - 616 Seiten
...right angles. THEOREM XIX. IN any figure whatever, the Sum of all the Inward Angles, taken together, is equal to Twice as many Right Angles, •wanting four, as the Figure has Sides. Let ABCDE be any figure ; then the sum of all its inward angles, A + B + c+ II+E, is equal to twice...
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Dictionary of the Mathematical and Physical Sciences, According to the ...

James Mitchell - 1823 - 666 Seiten
...adjacent sides; as the angles a, 6, c, &c. The sum of all the inward angles of any tight-lined figure, is equal to twice as many right angles, wanting four, as the figure has sides. ' An ANGLE at the Centre of a Circle, is that whose angular poim is at the centre. An ANGLE at the...
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A Treatise on Practical Mensuration in Eight Parts ...

Anthony Nesbit - 1824 - 476 Seiten
...formed. \ NOTE. The sum of all the interior angles of any polygon, whether regular or irregular, is equal to twice as many right angles, wanting four, as the figure has sides. PROBLEM XXVIII. To jind a mean proportionailttween two given lines. Let the given lines be AB = 32,...
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Elements of Geometry: Being Chiefly a Selection from Playfair's Geometry

John Playfair - 1829 - 210 Seiten
...right angles'. Let ABCDE be any rectilineal figure; all its interior angles A, B, C, D, E, are together equal to twice as many right angles, wanting four, as the figure has sides. For any rectilineal figure ABCDE can be divided into as many triangles as it has sides, by drawing...
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