 | Wooster Woodruff Beman, David Eugene Smith - 1895 - 344 Seiten
...diameter which bisects a chord is perpendicular to it. ForvAE=EC, and OA = OC, and OE = OE, .-. A AEO-S A CEO, and Z OEA = Z CEO, by I, th. 12. 2. The perpendicular...center of the circle and bisects the subtended arcs. Theorem 6. All points in a chord lie within the circle; and all points in the same line, but not in... | |
 | Wooster Woodruff Beman, David Eugene Smith - 1899 - 416 Seiten
...equidistant from A and C. Hence, being determined by these points, it is JL to AC, by I, prop. XLI. 2. The perpendicular bisector of a chord passes through...on the perpendicular bisector of the chord, by I, prop. XLI. PROPOSITION VI. 185. Theorem. All points in a chord lie within the circle ; and all points... | |
 | Wooster Woodruff Beman, David Eugene Smith - 1899 - 272 Seiten
...equidistant from A and C. Hence, being determined by these points, it is J- to AC, by I, prop. XLI. 2. The perpendicular bisector of a chord passes through...center of the circle and bisects the. subtended arcs. PROPOSITION VI. 185. Theorem. All points in a chord lie within the circle ; and all points in the same... | |
 | Wooster Woodruff Beman, David Eugene Smith - 1899 - 400 Seiten
...equidistant from A and C. Hence, being determined by these points, it is .l . to AC, by I, prop. XLI. 2. The perpendicular bisector of a chord passes through...center of the circle and bisects the subtended arcs. PROPOSITION VI. 185. Theorem. All points in a chord lie within the circle ; and all points in the same... | |
 | Arthur Schultze, Frank Louis Sevenoak - 1901 - 396 Seiten
...is the usual means of proving : (1) The equality of lines ? (2) The equality of arcs ? 179. COR. A perpendicular bisector of a chord passes through the center of the circle. Ex. 313. If two chords are equal, the perpendiculars from the center upon the chords are equal. Ex.... | |
 | Arthur Schultze, Frank Louis Sevenoak - 1902 - 394 Seiten
...is the usual means of proving : (1) The equality of lines ? (2) The equality of arcs ? 179. COR. A perpendicular bisector of a chord passes 'through the center of the circle. Ex. 313. If two chords are equal, the perpendiculars from the center upon the chords are equal. Ex.... | |
 | Arthur Schultze - 1901 - 260 Seiten
...is the usual means of proving : (1) The equality of lines ? (2) The equality of arcs ? 179. COR. A perpendicular bisector of a chord passes through the center of the circle. Ex. 313. If two chords are equal, the perpendiculars from the center upon the chords are equal. Ex.... | |
 | Arthur Schultze - 1901 - 392 Seiten
...is the usual means of proving : (1) The equality of lines ? (2) The equality of arcs ? 179. COR. A perpendicular bisector of a chord passes through the center of the circle. Ex. 313. If two chords are equal, the perpendiculars from the center upon the chords are equal. Ex.... | |
 | Wooster Woodruff Beman, David Eugene Smith - 1903 - 400 Seiten
...equidistant from A and C. Hence, being determined by these points, it is J_ to AC, by I, prop. XLI. 2. The perpendicular bisector of a chord passes through...the center of the circle and bisects the subtended ares. PROPOSITION VI. 185. Theorem. All points in a chord lie within the circle ; and all points in... | |
 | Fletcher Durell - 1911 - 553 Seiten
...A diameter which bisects a chord (shorter than a diameter) is perpendicular to the chord. 223. COR. 2. The perpendicular bisector of a chord passes through the center of the circle, and bisects the arcs subtended by the chord. 224. COR. 3. A line from the center perpendicular to a chord bisects the... | |
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XLI. 2. The perpendicular bisector of a chord passes through the center of the circle and bisects the subtended arcs. 
