 | 1827 - 600 Seiten
...that exertion of Boring force which, betides overcomdiameter of the cylinder in inches, by the motion of the piston in feet per minute, and divide the product by C050 ; the quotient is the power of the engine in horse power.t Example. — Cylinder 23J inches diameter,... | |
 | Perry Fairfax Nursey - 1827 - 588 Seiten
...power.* RULE. — Multiply the gquare of the 871 diameter of the cylinder in inches, by the motion of the piston in feet per minute, and divide the product by 6050 ; the quotient is the power of the engine in horse power.-)Example. —Cylinder 23J inches diameter,... | |
 | John E. Fuller - 1846 - 82 Seiten
...Diameter of the cylinder in inches, subtract 1, square the remainder, multiply the square by the velocity of the piston in feet per minute, and divide the product by 5640. The quotient will be the number required. CONDENSING ENGINES. Proportion of the Cylinder. —... | |
 | 1847 - 190 Seiten
...at any density requiredRule — Multiply 375 times the area of the cylinder in feet by the velocity of the piston in feet per minute, and divide the product by the volume of steam to 1 of water at the density required, (see Table, page 91 ;) and the quotient... | |
 | Thomas Kelt - 1849 - 424 Seiten
...any density required. Ride. — Multiply 375 times the area of the cylinder in feet by the velocity of the piston in feet per minute, and divide the product by the volume of steam to 1 of water at the density required, (see Table, page 91 ;) and the quotient... | |
 | Oliver Byrne - 1851 - 310 Seiten
...diameter of the cylinder in inches by the pressure on the piston in pounds per square inch, and by the speed of the piston in feet per minute, and divide the product by 120,000 ; the quotient is the power of the engine in nominal horses power. If the pressure upon the... | |
 | John Bourne - 1851 - 346 Seiten
...diameter of the cylinder, multiply by the effective pressure per square inch, and by the Fig. 340. motion of the piston in feet per minute, and divide the product by 42,017, which gives the same result. A horse-power is represented by a load of 33,000 Ibs., raised... | |
 | Septimus Norris - 1852 - 356 Seiten
...diameter of the cylinder in inches, subtract 1, square the remainder, multiply the square by the velocity of the piston in feet per minute, and divide the product by 5040- The quotient will be the number requiredGENERAL PROPORTIONS OF CONDENSING ENGINESCylinder —... | |
 | John Bourne (C.E.) - 1853 - 344 Seiten
...diameter of the cylinder in inches by the pressure on the piston in pounds per square inch, and by the speed of the piston in feet per minute, and divide the product by 120,000 ; the quotient is the power of the engine in nominal horses power. If the pressure upon the... | |
 | 1855 - 420 Seiten
...any density required. Mule. — Multiply 375 times the area of the cylinder in feet by the velocity of the piston in feet per minute, and divide the product by the volume of steam to 1 of water at the density required, (see Table, page 91 ;) and the quotient... | |
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Multiply the area of the piston in square inches by the average force of steam in pounds and by the velocity of the piston in feet per minute and divide the product by 33,000 pounds. Seven-tenths of the quotient equals the effective power. 
