| Edmond Landolt - 1886 - 638 Seiten
...I' becomes negative, and the formula 156 gives for a likewise a negative value. Hence the image is on the same side of the lens as the object. It is virtual, has the same direction as, and is larger than, the object. It increases in size in proportion... | |
| Simon Henry Gage - 1891 - 238 Seiten
...images, and that the eye forms an integral part of it. AB. The object within the principal focus. A' B'. The virtual image on the same side of the lens as...with dotted lines, as it has no actual existence. A9 B'. Retinal image of the object (AB). The virtual image is simply a projection of the retinal image... | |
| Simon Henry Gage - 1891 - 238 Seiten
...images, and that the eye forms an integral part of it. A B. The object within the principal focus. A' B'. The virtual image on the same side of the lens as the object. It is indicated with dotted Ihies, as it has no actual existence. A2 B'. Retinal image of the object (AB). The virtual image is... | |
| Henry Smith Carhart - 1894 - 360 Seiten
...the object, is necessarily positive, q must be positive and smaller than p. The image is therefore on the same side of the lens as the object, it is virtual and nearer the lens than the object. Thus in Fig. 136, A is the source, and the ray AB, after... | |
| Simon Henry Gage - 1899 - 272 Seiten
...that the eye forms an integral part of it. A1 /?'. The object w ithin the principal focus. A" /?3. The virtual image on the same side of the lens as...with dotted lines, as it has no actual existence. ff' A'. Retinal image of the object (A1 #'). The virtual image is simply a projection of the retinal... | |
| Dan J. Goldstein - 1999 - 232 Seiten
...image on the side of the lens away from the object, while the other pair of aplanatic points gives a virtual image on the same side of the lens as the object but further from the lens. In the early 19th century Lister (who was father of the surgeon who became... | |
| Christopher G. De Pree, Ph.D. - 2010 - 208 Seiten
...converging lens, an object placed anywhere within the focal length cannot form a real image, and one sees a virtual image on the same side of the lens as the object. In this case, the lens is acting as a magnifying glass. There is also a mathematical way to determine... | |
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