 | Robert Simson - 1762 - 488 Seiten
...ferences. • Let ABC, DEF be equal circles, and the equal angles BGC, EHF at their centers, and BAC, EDF at their circumferences, the circumference BKC...centers are equal ; therefore the two fides BG; GC, arc equal to the two EH, HF; and the angle at G is equal to the angle at H; therefore the bafe BC is... | |
 | Euclid - 1765 - 492 Seiten
...drawn from their centres will be equal : Therefore the two fides BG, G c are equal to the two fides EH, HF, and the angle at G is equal to the angle at H : Therefore [by 4. i.] the bi,fe B c is equal to the bafe B F. And becaufe the angle at A is equal to the angle... | |
 | Robert Simson - 1775 - 534 Seiten
...circumferences. Let ABC, DEF be equal circles, and the equal angles BGC, EHF at their centers, and BAC, EDF at their circumferences : The circumference BKC...drawn from their centers are equal : therefore the two ftdes BG, GC, are equal to the two EH, HF ; and the angle at G is equal to the angle at II ; therefore... | |
 | Robert Simson - 1781 - 534 Seiten
...circumferences. Let ABC, DEF be equal circles, and the equal angles BGC, EHFat their centers, and BAC, EDF at their circumferences. the circumference BKC...fides BG, GC, are equal to the two EH, HF ; and the angte 'CE at G is equal to the angle at H ; therefore the bafe BC is equal ' >, 4- <• to the bafe... | |
 | Euclid - 1781 - 552 Seiten
...circumferences. Let ABC, DEF be equal circles, and the equal angles BGC, EHF at their centres, and BAC, EDF at their circumferences : The circumference BKC...DEF are equal, the ftraight lines drawn from their centres are equal : Theretore the two fides BG, GC, are equal to the two EH, I IF ; and the angle at... | |
 | Euclid, John Playfair - 1795 - 462 Seiten
...circumferences. .-'let Let ABC, DEF be equal circles, and the equal angles BGC, EHF at their centres, and BAC, EDF at their circumferences : the circumference BKC...Join BC, EF< and becaufe the circles ABC, DEF are eqtial, the ftraXght Ijnes dijwvn from, their centres are «qual: therefore the two fides, ^G, GC,... | |
 | Alexander Ingram - 1799 - 374 Seiten
...and becaufe the circles ABC, DEF are equal, *— '"V^^ the flraight lines drawn from their centres are equal : Therefore the two fides BG, GC are equal...angle at G is equal to the angle at H ; therefore the a 4. i. bafe BC is equal a to the bafe EF : And becaufe the angle at A lIn.def-3. 's equal to the angle... | |
 | John Playfair, Euclid - 1804 - 468 Seiten
...Join BC, EF ; and becaufe th$ circles ABC, DEF are equal, the ftraight lines drawn from their centres are equal: therefore the two fides BG, GC, are equal...HF; and the angle at G is equal to the angle at H j there • 4.i. fore the bafe BC is equal » to the bafe EF : and becaufe the angle at A is equal... | |
 | John Playfair - 1806 - 320 Seiten
...ABC, DEF are equal, the straight lines drawn from their centres are equal j therefore the two sides BG, GC are equal to the two EH, HF ; and the angle at G is equal to the angle at H ; therea 4. 1. fore the base BC is equal* to the base EF. Because the angle at A is equal to the angle... | |
 | Robert Simson - 1806 - 546 Seiten
...circumferences. Let ABC, DEF be equal circles, and the equal angles BGC, EHF at their centres, and BAC, EDF at their circumferences : the circumference BKC...is equal to the circumference ELF. Join BC, EF; and because the circles ABC, DEF are equal, the straight lines drawn from their centres are equal : therefore... | |
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ELF. Join BC, EF ; and because the circles ABC, DEF are equal, the straight lines drawn from their centres are equal: therefore the two sides BG, GC, are equal to the two EH, HF ; and the angle at G is equal to the angle at H ; therefore the base BC is... 
