 | Henry Adcock - 1832 - 100 Seiten
...weight in equilibrium. EXAMPLE. Weight to be raised 42 cwt. Power to be applied 6 cwt. Hence, 42 -f- 6 = 7, The distance from the power to the fulcrum,...times greater than from the fulcrum to the weight. For T of length = f of weight = 36 cwt.—Fulcrum. $ of length = } of weight = 6 cwt.—Power. CASE... | |
 | Henry Adcock - 1839 - 96 Seiten
...weight in equilibrium. . EXAMPLE. Weight to be raised 42 cwt. Power to be applied 6 cwt. Hence, 42 -f- 6 = 7, The distance from the power to the fulcrum,...times greater than from the fulcrum to the weight. For \ of length = ® of weight = 36 cwt. — Fulcrum. 7 of length = } of weight = 6 cwt. — Power.... | |
 | Henry Adcock - 1839 - 96 Seiten
...support the weight in equilibrium. Weight to be raised 42 cwt. Power to be applied 6 cwt Hence, 42 -f- 6 = 7, The distance from the power to the fulcrum,...times greater than from the fulcrum to the weight. For 7 of length = f of weight = 36 cwt. — Fulcrum. ? of length = } of weight = 6 cwt. — Power.... | |
 | William Templeton - 1846 - 518 Seiten
...effective weight of the lever, multiply the remainder by the distance between the fulcrum and the valve, divide the product by the distance between the fulcrum and the weight, and the quotient is the weight in Ibs. required to be placed upon the lever at that distance. 2. —... | |
 | Charles Haslett - 1855 - 482 Seiten
...effective weight of the lever, multiply the remainder by the distance between the fulcrum and the valve, and divide the product by the distance between the fulcrum and the weight, and 'tile quotlenVis''-^ weight' in Ibk rfequii-'e^l to be placed upon the lever at that distance.... | |
 | Charles Haslett - 1855 - 544 Seiten
...effective weight of the lever, multiply the remainder by the distance between the fulcrum and the valve, and divide the product by the distance between the fulcrum and the weight, and the quotient is the weight in Ib*. required to be placed upon the lever at that distance. 2. When... | |
 | Charles W. Hackley - 1856 - 530 Seiten
...effective weight of the lever, multiply the remainder by the distance between the fulcrum and the valve, and divide the product by the distance between the fulcrum and the •weight, and the quotient is the weight in Ibs. required to be placed | upon the lever at that distance. I 2.... | |
 | W.E. WORTHEN - 1857 - 600 Seiten
...the weight in equilibrium. Weight to be supported, 42 cwt.; power to be applied, 6 cwt. Hence, 42 ~ 6 '== 7. The distance from the power to the fulcrum,...the power and the fulcrum by the power, and divide tjie product by the distance between the fulcrum and the weight. A bar 10 feet long is arranged as... | |
 | Charles Haslett, Charles William Hackley - 1859 - 574 Seiten
...effective weight of the lever, multiply the remainder by the distance between the fulcrum and the valve, and ! divide the product by the distance between the fulcrum and the the quotient will give the difference of leverage necessary to support the weight in equilibrio. Hence,... | |
 | 1883 - 652 Seiten
...effective weight of the lever ; multiply the remainder by the distance between the fulcrum and the valve, divide the product by the distance between the fulcrum and the weight, and the quotient is the weight in pounds required to be placed upon the lever at that distance.—... | |
| |
To find the weight that will be supported by a known amount of power, the position of the fulcrum being given : Multiply the distance between the power and the fulcrum by the power, and divide the product by the distance between the fulcrum and the weight. 