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Books Bücher 1 - 10 von 86 in If two straight lines cut one another within a circle, the rectangle contained by...
" If two straight lines cut one another within a circle, the rectangle contained by the segments of one of them, is equal to the rectangle contained by the segments of the other. "
Military examinations. Mathematical examination papers, set for entrance to ... - Seite 18
von Woolwich roy. military acad - 1880
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An Easy Introduction to the Mathematics: In which the Theory and ..., Band 2

Charles Butler - 1814
...If two straight lines cut one another, and the rectangle contained by the segments of one of them, be equal to the rectangle contained by the segments of the other, the circumference which passes through three of the extremities of the two given straight lines, shall...
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An Elementary Treatise on the Geometrical and Algebraical Investigation of ...

Daniel Cresswell - 1817 - 436 Seiten
...be equal to one another. (LXXV.) To divide a given straight line into two parts, so that the square of the one shall be equal to the rectangle contained by the other and a given straight line. (LXXVI.) If a given circle be cut by any number of circles, which...
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A Supplement to the Elements of Euclid

Daniel Cresswell - 1819 - 410 Seiten
...another. PROP. LXXXI. 106. PROBLEM. To divide a given straight line into two parts, so that the square of the one shall be equal to the rectangle contained by the other and a given straight line. Let AB and L be two given finite straight F Gr E lines : It is required...
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Geometrical Problems Deducible from the First Six Books of Euclid, Arranged ...

Miles Bland - 1819 - 377 Seiten
...part ; (m) being whole or fractional. 11. To divide a given line into two such purls, that the square of the one shall be equal to the rectangle contained by the other and a given line. 12. A straight line being given in magnitude and position ; to draw to it,...
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Geometrical Problems Deducible from the First Six Books of Euclid: Arranged ...

Miles Bland - 1819 - 377 Seiten
...part ; (m) being whole or fractional. 11. To divide a given line into two such parts, that the square of the one shall be equal to the rectangle contained by the other and a given line. 12. A straight line being given in magnitude aud position ; to draw to it,...
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The First Six and the Eleventh and Twelfth Books of Euclid's Elements: With ...

Euclid - 1837 - 390 Seiten
...IF two chords of a circle cut one another, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other. In the circle ABCD, let the two chords AC, BD cut one another in the point E : the rectangle AE.EC is...
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A companion to Euclid: being a help to the understanding and remembering of ...

Euclides - 1837
...straight lines within a circle cut each other, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other. • In case 1st, E is the centre of the 0, and evident that AE x EC = BE x ED. it is Steps of the Demonstration...
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Euclid's Elements [book 1-6] with corrections, by J.R. Young

Euclides - 1838
...cut off, containing an angle equal to the given angle D. Which was to be done. PROP. XXXV. THEOR. If two straight lines cut one another within a circle, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other. Let the two straight...
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The Elements of Euclid; viz. the first six books,together with the eleventh ...

Euclides - 1841
...cut off, containing an angle equal to the given angle D. Which was to be done. PROP. XXXV. THEOR. If two straight lines cut one another within a circle, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other. Let the two straight...
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A system of practical mathematics; being no.xvi. of a new series of school-books

1845
...PROPOSITION LXV — THEOREM. If two chords, AB, CD, cut one another in a point E, within a circle A CD, the rectangle contained by the segments of the one...rectangle contained by the segments of the other. That is, the rectangle AE-EB=CE-ED. Join CA and BD, then the Z.CAE is = the Z.BDE ; for they stand...
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