Skeleton Structures: Especially in Their Application to the Building of Steel & Iron BridgesVan Nostrand, 1867 - 96 Seiten |
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according admissible strain alter amount ascer axes bar-head beam BEAM BRIDGES bolt Britannia Bridge carry Celsius Centigrade components connection connection-points construction dead weight decrease deflection determined diagonal direction displacings distributed equal equations exactly example exposed feet span figure firstly fixed foot length formula g tons geometrical gives heat horizontal iron LATTICE GIRDERS limit of elasticity load per running modulus of elasticity original length P₁ parallelogram of forces Plate platform pression pressure prolongation proportion represents resist resulting force rigidity roadway rolling load running foot S₂ shown shows sible strain single bars single line Skeleton Bridge skeleton girder Skeleton Structures square inch ß Vx steel strains caused superfluous bars suspended bridges tensile force tension and compression tion tons per inch tons per running Total weight trussed bridges ture v₁ vertical weight G whilst
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Seite 28 - AC and BC represent bars, which are connected at A and B by bolts to a wall piece, and at C by bolt to each other. A weight P acts on the bolt C, and we want to ascertain the strain in the two bars. Firstly We have to apply two rectangular axes through (7, and because AC is horizontal, and CP vertical, we take these directions as the axes.
Seite 30 - For axes we always take one horizontal and one vertical line, and because we have three free connection-points, 1, 2, and 4, we can form six equations, by which we are able to ascertain all the six strains at once. For point 2 we have the same equations as in the previous example, by introducing...
Seite 32 - JFiff.12 . done in the same way ; one strain is calculated after the other without difficulty. I will mention here at once, that the same calculation can be used for a trussed structure, as in Fig.
Seite 28 - ... and because AC is horizontal, and CP vertical, we take these directions as the axes. The strain in the bar...
Seite 32 - We have still to ascertain the strains 8 ol and 8 13 , which we are able to do by the equations of point (1), after having altered them in the same way : 8 <- ^oi 8 P a U I . AJ la - J.
Seite 29 - By this all bars are determined in length and position, and we can proceed to resolve the forces. For axes we always take one horizontal and one vertical line, and because...
Seite 6 - That each bar is exposed to tension and compression only in the direction of its longitudinal axis, which is the most favorable condition possible.