Elements of Geometry and Plane Trigonometry: With an Appendix, and Copious Notes and IllustrationsA. Constable & Company, 1817 - 432 Seiten |
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Seite 39
... Wherefore ABC and BCD are equal to two right angles , and the A D lines AB and DC ( I. 22. cor . ) parallel ; for the same rea- son , ABC and BAD being together equal to two right an- gles , the sides BC and AD , which limit them , are ...
... Wherefore ABC and BCD are equal to two right angles , and the A D lines AB and DC ( I. 22. cor . ) parallel ; for the same rea- son , ABC and BAD being together equal to two right an- gles , the sides BC and AD , which limit them , are ...
Seite 42
... Wherefore the triangles ADH and DEM , having two angles respectively equal and the inter- jacent sides AD , DE — are ( I. 20. ) equal , and consequent- ly AH is equal to DM . In the same manner , the tri- angle ADH is proved to be equal ...
... Wherefore the triangles ADH and DEM , having two angles respectively equal and the inter- jacent sides AD , DE — are ( I. 20. ) equal , and consequent- ly AH is equal to DM . In the same manner , the tri- angle ADH is proved to be equal ...
Seite 44
... Wherefore EB , being equal to AC ( I. 26. ) which is equal to DF , is itself e- qual to DF . Add BD to each , A. and ED is equal to BF ; but EA is equal to BC ( I. 26. ) , and the interior angle AED is equal to the exterior angle CBF ...
... Wherefore EB , being equal to AC ( I. 26. ) which is equal to DF , is itself e- qual to DF . Add BD to each , A. and ED is equal to BF ; but EA is equal to BC ( I. 26. ) , and the interior angle AED is equal to the exterior angle CBF ...
Seite 52
... Wherefore the triangles ABC and AFK , thus having two an- gles of the one respectively equal to those of the other , and the interjacent side AF equal to AB , are equal ( 1. 20. ) , and consequently the side AC is equal to AK . Hence ...
... Wherefore the triangles ABC and AFK , thus having two an- gles of the one respectively equal to those of the other , and the interjacent side AF equal to AB , are equal ( 1. 20. ) , and consequently the side AC is equal to AK . Hence ...
Seite 61
... Wherefore the squares of AB , BC are toge- ther equivalent to twice the squares of AD and DB . Cor . Hence if a straight line AB be bisected in C and cut unequally in D , whether by in- ternal or external section , the squares A CD ...
... Wherefore the squares of AB , BC are toge- ther equivalent to twice the squares of AD and DB . Cor . Hence if a straight line AB be bisected in C and cut unequally in D , whether by in- ternal or external section , the squares A CD ...
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Elements of Geometry, and Plane Trigonometry: With an Appendix, and Very ... University Professor Emeritus John Leslie, Sir Keine Leseprobe verfügbar - 2016 |
Häufige Begriffe und Wortgruppen
ABCD adjacent angle altitude angle ABC angle ADB angle BAC base AC bisect centre chord circle circumference consequently construction contained angle cosine decagon denote describe diameter difference distance diverging lines divided draw equal to BC equilateral triangle equivalent to twice evidently exterior angle given greater half Hence hypotenuse inscribed isosceles triangle join let fall likewise measure parallel perpendicular point G polygon PROB PROP Proposition quadrilateral figure quantities radius ratio rectangle rectangle contained rectilineal figure rhomboid right angles right-angled triangle Scholium segments semicircle semiperimeter sequently side AC sinB sine square of AB square of AC straight line tangent THEOR tion triangle ABC twice the rectangle twice the square vertex vertical angle whence Wherefore