Elements of Geometry and Plane Trigonometry: With an Appendix, and Copious Notes and IllustrationsA. Constable & Company, 1817 - 432 Seiten |
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Seite 20
... equal . The angles BAC and BCA at the base of the isosceles triangle ABC are equal . For draw ( I. 5. ) BD bisecting the vertical angle ABC . Because , by hypothesis , AB is equal to BC , the side BD common to the two tri- angles BDA ...
... equal . The angles BAC and BCA at the base of the isosceles triangle ABC are equal . For draw ( I. 5. ) BD bisecting the vertical angle ABC . Because , by hypothesis , AB is equal to BC , the side BD common to the two tri- angles BDA ...
Seite 22
... BC be not greater than AB , it must be either equal or less . But it cannot be equal , be- cause the angle CAB would then be equal to ACB ( I. 10. ) ; nor can BC be less than AB , for then AB would be greater than BC , and consequently ...
... BC be not greater than AB , it must be either equal or less . But it cannot be equal , be- cause the angle CAB would then be equal to ACB ( I. 10. ) ; nor can BC be less than AB , for then AB would be greater than BC , and consequently ...
Seite 23
... equal to AB ; the remainder EC is less than the third side BC . For the two sides AB and BC are to- gether greater than AC ( I. 14. ) ; take away the equal lines AB and AE , and there remains BC greater than EC , or EC is less than BC ...
... equal to AB ; the remainder EC is less than the third side BC . For the two sides AB and BC are to- gether greater than AC ( I. 14. ) ; take away the equal lines AB and AE , and there remains BC greater than EC , or EC is less than BC ...
Seite 24
... BC , being greater than AE and EC , which are themselves greater than AD and DC , must be still greater than AD and ... equal ; and those more remote are greater than such as are nearer . Of the straight lines CG , CE , CD , and CF drawn from ...
... BC , being greater than AE and EC , which are themselves greater than AD and DC , must be still greater than AD and ... equal ; and those more remote are greater than such as are nearer . Of the straight lines CG , CE , CD , and CF drawn from ...
Seite 26
... AB one of the sides to be not greater than BC or EF , and ( I. 4. ) draw BG equal to EF making an angle ABG equal to DEF , join AG and GC . Because AB and BG are equal to DE and EF , and the contained angle ABG is equal to DEF ; the ...
... AB one of the sides to be not greater than BC or EF , and ( I. 4. ) draw BG equal to EF making an angle ABG equal to DEF , join AG and GC . Because AB and BG are equal to DE and EF , and the contained angle ABG is equal to DEF ; the ...
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Elements of Geometry, and Plane Trigonometry: With an Appendix, and Very ... University Professor Emeritus John Leslie, Sir Keine Leseprobe verfügbar - 2016 |
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ABCD adjacent angle altitude angle ABC angle ADB angle BAC base AC bisect centre chord circle circumference consequently construction contained angle cosine decagon denote describe diameter difference distance diverging lines divided draw equal to BC equilateral triangle equivalent to twice evidently exterior angle given greater half Hence hypotenuse inscribed isosceles triangle join let fall likewise measure parallel perpendicular point G polygon PROB PROP Proposition quadrilateral figure quantities radius ratio rectangle rectangle contained rectilineal figure rhomboid right angles right-angled triangle Scholium segments semicircle semiperimeter sequently side AC sinB sine square of AB square of AC straight line tangent THEOR tion triangle ABC twice the rectangle twice the square vertex vertical angle whence Wherefore