| D. Tierney - 1877
...not intersect, and therefore the construction for the triangle required would fail. 2. Parallelograms **upon the same base, and between the same parallels, are equal to one another.** Shew that if two triangles have two sides of the one equal to two sides of the other, each to each,... | |
| Alfonzo Gardiner - 1878
...= _. 7. The difference of two numbers is 14, and their sum is 48 : find the numbers. 8. Prove that **triangles upon the same base, and between the same parallels, are equal to one another.** 9. What do you mean by the " complements of a parallelogram " and by " applying a parallelogram to... | |
| Thomas Hunter - 1878 - 132 Seiten
...same reason EFGH is equal to ABGH. Hence ABCD and EFGH are equal (Ax. 1). PROPOSITION VIII.—THEOREM. **Triangles upon the same base, and between the same parallels, are equal** ABC and ABD have the same base, AB, and be between the same parallels, AB and CD; then will these two... | |
| J T. Amner - 1878
...equal to two right angles. What ratio does the angle of a regular hexagon bear to a right angle ? 2. **Triangles upon the same base and between the same parallels are equal.** A line drawn through the middle points of the sides of a triangle is parallel to the base. 3. In any... | |
| Moffatt and Paige - 1879
...ACD B. Therefore, the opposite sides and angles, etc. . QED Proposition XXXV. Theorem. Parallelograms **upon the same base, and between the same parallels, are equal to one another. Let the** parallelograms ABCD, EBCF be upon the same base BC, and between the same parallels AF, B C. Then the... | |
| Great Britain. Civil Service Commission - 1879
...same side ; and also the two interior angles on the same side together equal to two right angles. 3. **Triangles upon the same base and between the same parallels are equal to one another. Let** ABC, ABD, be two equal triangles upon the same base AB, and on opposite sides of it ; if CD be joined... | |
| James Hamblin Smith - 1879 - 349 Seiten
...are on the same base EH and between the same || s ; .: lUABCD=OEFGH. QED PROPOSITION XXXVII. THEOREM. **Triangles upon the same base, and between the same parallels, are equal to one another.** O Let A a ABC, DBC be on the same base BC and between the same \\a AD, BC. Then must A ABC= &DBC. From... | |
| W J. Dickinson - 1879 - 36 Seiten
...angle. 36. Parallelograms upon equal bases and between the same parallels are equal to one another. 37. **Triangles upon the same base and between the same parallels are equal to one another.** Any point P is taken in the line joining an angular point A of a triangle to the middle point of the... | |
| Great Britain. Parliament. House of Commons - 1879
...possible ? Show how the construction will fail if the condition is not observed. 4. Parallelograms **upon the same base and between the same parallels are equal to one another.** 5. In any right-angled triangle the square which is described upon the side subtending the right angle... | |
| Euclides - 1879
...opposite angles : these lines trisect the given line. PROPOSITION XXXV. THEOREM. Parallelograms on the **same base, and between the same parallels, are equal to one another. Let the** / — 7s ABCD, EBCF be on the same base BC, and between the same ||s AF, BC. Then shall /— 7 ABCD... | |
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