 | William Pease - 1856 - 108 Seiten
...to meet these perpendiculars, and the required rectangle will be formed. REASON : " Parallelograms, upon the same base, and between the same parallels," are equal to each other. (Euclid, Book I. Prop. 35.) PROBLEM LXX. To make a rectangle, one of its sides being given,... | |
 | Euclides - 1858 - 248 Seiten
...extensive use in the construction and measurement of Geometrical Figures. \ TO \ i / PROP. 37. — THEOR. Triangles upon the same base and between the same parallels are equal to one another. CONSTRUCTION. — Pst. 2. A st. line may be produced in a st. line. P. 31. Through a given point to... | |
 | War office - 1858 - 578 Seiten
...If the words printed above in italics be omitted, would the proposition as then stated be true ? 2. Triangles upon the same base, and between the same parallels, are equal to one another. Divide a given triangle into four equal parts. 3. "What is a rectangle ? If a straight line be divided... | |
 | Euclides - 1868 - 88 Seiten
...HC 4 P. 33. 5 Def. A. 6 D. 5. H. 7 P. 35. 8 P. 85. 9 Ax. 1. 10 Becap. • PilOP. XXXVII. Тикоа. Triangles upon the same base and between the same parallels are equal to one ano CON. Pst. 2. P. 31. Def. A. DEM. P. 35. 34. Ax. 7. SCHOL. PIIOP. XXXVIII. TIIEOU. Triangles upon... | |
 | Sandhurst roy. military coll - 1859 - 672 Seiten
...shall be greater than the base of the other. 2. Define a parallelogram ; prove that parallelograms upon the same base and between the same parallels are equal to one another. 3. If a straight line be divided into any two parts, the squares of the whole line and of one of the... | |
 | Robert Potts - 1860 - 380 Seiten
...-BCdivides the parallelogram A CDB into two equal parts. QED PROPOSITION XXXV. THEOREM. Parallelograms upon the same base, and between the same parallels, are equal to one another. Let the parallelograms AB CD, EBCF be upon the same base 2? C, and between the same parallels AF, BC. Then... | |
 | Euclides - 1860 - 288 Seiten
...parallelogram EBCH ; therefore (Ax. 1) the parallelogram ABCD is equal to EFGH. PROPOSITION XXXVII. THEOREM. Triangles upon the same base, and between the same parallels, are equal to one another. Given the triangles ABC and DEC upon the same base BC, and between the same parallels AD and BC ; to... | |
 | Royal college of surgeons of England - 1860 - 336 Seiten
...triangle are greater than the third. Show that the difference of any two sides is less than the third. 5. Triangles upon the same base and between the same parallels are equal to one another. 6. If the square described upon one of the sides of a triangle be equal to the squares described upon... | |
 | Henry William Watson, Edward John Routh - 1860 - 240 Seiten
...rectangle contained by AB and CD, the rect. AB, CD. 1. DEFINE parallel straight lines. Parallelograms upon the same base, and between the same parallels, are equal to one another. If a straight line DME be drawn through the middle point M of the base BC of a triangle ABC, so as... | |
 | John Playfair - 1860 - 332 Seiten
...same EBCH : Therefore also the parallelogram ABOI? it «qual to EFGH. PROP. XXXVII. THEOR. Trim gles upon the same base, and between the same parallels, are equal to ont another. Let the triangles ABC, DBC be upon the same base BC, and between the same parallels, AD,... | |
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TRIANGLES upon the same base, and between the same parallels, are equal to one another. 
