| George Bruce Halsted - 1886 - 394 Seiten
...it produced, together with the square on half the sect bisected, is equivalent to the square on the **line which is made up of the half and the part produced.** 299. By 294, (a + by + a* = a* + 2ab + b* + «*. By the associative law, a* + 2ab + b* + a* = aa* +... | |
| Richard Anthony Proctor - 1887 - 202 Seiten
...sq. on CD + sq. on CB + sq. on CD (by VII.)' = 2 sq. on AC + 2 sq. on CD (---CB = AC) PROP. X. — **Let the straight line AB be bisected in C, and produced to** D : then, the squares on AD, DB shall be double of the squares on AC, C D. A c BD II ! I By IV., Sq.... | |
| E. J. Brooksmith - 1889 - 354 Seiten
...part of it produced, together with the square of half the line bisected, is equal to the square of the **straight line which is made up of the half and the part produced.** 5. In obtuse-angled triangles, if a perpendicular be drawn from any of the acute angles to the opposite... | |
| Dalhousie University - 1889 - 220 Seiten
...part of it produced together with the square of half the line bisected is equal to the square of the **line which is made up of the half and the part produced** : also deduce the geometrical proof of the algebraic formula 5. In a circle the greater chord is nearer... | |
| Edward Mann Langley, W. Seys Phillips - 1890 - 538 Seiten
...the part produced, together with the square on half the line bisected, is equal to the square on the **straight line which is made up of the half and the part produced. Let** AB be bisected at C and produced to D ; ACBD K 7TT M GV then rect. AD, DB with sq. on CB=sq. on CD.... | |
| Royal Military College, Sandhurst - 1890 - 144 Seiten
...part of it produced, together with the square on half the line bisected, is equal to the square on the **straight line which is made up of the half and the part produced.** If ABC be an isosceles triangle, and D be a point on the base BC produced ; show that the difference... | |
| Queensland. Department of Public Instruction - 1890 - 530 Seiten
...part of it produced, together with the square on half the line bisected, is equal to the square on the **straight line which is made up of the half and the part produced.** 3. Demonstrate that case of Kuc. II. 13 where the perpendicular falls within the given triangle. 4.... | |
| Rupert Deakin - 1891 - 102 Seiten
...the part produced, together with the square on half the line bisected, is equal to the square on the **straight line which is made up of the half and the part produced.** 7. If a straight line be divided into any two parts, the squares on the whole line and on one of the... | |
| Henry Martyn Taylor - 1893 - 486 Seiten
...and the part of it produced, and the square on half the line bisected, is equal to the square on the **straight line which is made up of the half and the...part produced *. Let the straight line AB be bisected** at the point C, and produced to the point D : it is required to prove that the sum of the rectangle... | |
| Henry Martyn Taylor - 1895 - 708 Seiten
...and the part of it produced, and the square on half the line bisected, is equal to the square on the **straight line which is made up of the half and the...part produced *. Let the straight line AB be bisected** at the point C, and produced to the point D : it is required to prove that the sum of the rectangle... | |
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