 | Euclides, James Hamblin Smith - 1872 - 376 Seiten
...CJEFGH, i. 35. v they are on the same base EH and between the same IIs ; QED PROPOSITION XXXVII. THEOREM. Triangles upon the same base, and between the same parallels, are equal to one another. Let A s ABC, DBC be on same base BC and between same IIs AD, BC. Then must &ABC= A DBC. From B draw BE... | |
 | Euclid, Charles Peter Mason - 1872 - 216 Seiten
...ABCD and EFGH, being each equal to the parallelogram ABGH, Are equal to each other. PBOPOSITION XXXVU. Triangles upon the same base and between the same parallels are equal to each other. For the construction in this proposition we must be ableto draw a straight line from a... | |
 | Hugo Reid - 1872 - 148 Seiten
...produced. 142. If ote. — This illustrates the important geometrical truth, that — Parallelograms on the same base and between the same parallels are equal to one another; that is, equal in area. Fic.34 AEFD and ABCD are on the same base AD and between the same parallels... | |
 | Lewis Sergeant - 1873 - 182 Seiten
...decimals. (10.) 21 41 21 228 2000 _1824 1~7G, <fcc. (See Arith., § 61.) * 3. Show that parallelograms and triangles upon the same base and between the same parallels are equal to one another. (10.) (This appears to mean that parallelograms on the same base and between the same parallels are... | |
 | Henry Major - 1873 - 588 Seiten
...and DEC is the half of DBCF ; therefore ABC is equal to DEC. XXXVIII. — Triangles upon equal bases, and between the same parallels, are equal to one another. Let the triangles ABC, DEF, be upon equal bases BC, EF, and between the same parallels BF, AD. Produce AD both ways to the... | |
 | Edward Atkins - 1874 - 428 Seiten
...same base, and between the same parallels, are equal to one anot/ier. Let the triangles ABC, DBC be on the same base BC, and between the same parallels AD, BC ; The triangle ABC shall be equal to the triangle DBC. CONSTRUCTION. — Produce AD both ways, to the points E, F. Through B draw BE... | |
 | Euclides - 1874 - 342 Seiten
...divides the parallelogram ACDB into two equal parts. ~ QED PROPOSITION 35. — Theorem. Parallelograms upon the same base, and between the same parallels, are equal to one another. Let the parallelograms ABCD, EBCF be upon the same base BC, and between the same parallels AF, BC. Then the... | |
 | Edward Atkins - 1874 - 426 Seiten
...two equal parts. Therefore, the opposite sides, <fec. QED Proposition 35. — Theorem. Parallelograms upon the same base, and between the same parallels, are equal to one another. Let the parallelograms A BCD, EBCF be on the same base BC, and between the same parallels AF, BC; The parallelogram... | |
 | Euclides - 1874 - 120 Seiten
...The diagonals of a parallelogram bisect each other. PROPOSITION 35. THEOREM. Parallelograms on the same base, and between the same parallels, are equal to one another. .. Let the parallelograms ABCD, EBCFbe on the '• same base BC, and between the same parallels AF, BC: the parallelogram... | |
 | Braithwaite Arnett - 1874 - 130 Seiten
...to a given straight line of unlimited length from a given point without it. 2. Parallelograms on the same base and between the same parallels are equal to one another. 3. If a straight line be bisected, and produced to any point, the rectangle contained by the whole... | |
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TRIANGLES upon the same base, and between the same parallels, are equal to one another. 
