| Euclides - 1853
...diameter BC divides the parallelogram ACDB into two equal parts. QED PROP. XXXV. THEOREM. Parallelograms **upon the same base and between the same parallels, are equal to one another. Let the** parallelograms ABCD, EBCF, be upon the same base BC, and between the same parallels AF, BC; the parallelogram... | |
| Euclides - 1853 - 147 Seiten
...divides the parallelogram a С db into two equal parts. QED PROPOSITION XXXV. — THEOREM. Parallelograms **upon the same base, and between the same parallels, are equal to one another. LET the** parallelograms abСd, ebСf (see the second figure) be upon the same base b С, andbetween the same... | |
| Royal Military Academy, Woolwich - 1853
...BC divides the parallellogram ACDB into two equal parts. QED PROPOSITION XXXV. THEOR. Parallelograms **upon the same base, and between the same parallels, are equal to one another. Let the** parallelograms ABCD, KBCF be upon the same base BC, and between the same parallels AF; BC : the parallelogram... | |
| Thomas Lund - 1854 - 192 Seiten
...FG is equal to that ratio (170), and join DH. Then DHG is the triangle required. For BDC, BDF, being **triangles upon the same base and between the same parallels, are equal to one another** (41). Also A.ADE — &ADG; .'.adding to these equals the AABD, it is evident that ADGF = the polygon... | |
| John Playfair - 1855 - 318 Seiten
...same EBCH : Therefore also the parallelogram ABCQ i* *qual to EFGH. PROP. XXXVII. THEOR. Trim gles **upon the same base, and between the same parallels,...between the same parallels, AD, BC : The triangle ABC** is equal to the trian- E A. PF gle DBC. " ' ~ " ~ ~ Produce AD both ways to the points E, F, and through... | |
| Euclides - 1855
...only which are at the vertices of any two of its opposite angles. PROP. XXXV. THEOREM. Parallelograms **upon the same base, and between the same parallels, are equal to one another. Let the** parallelograms AС, B Г be upon the same base B С, and and between the same parallels AF, BС. The... | |
| Robert Potts - 1855
...times as great ? The line joining the bisections of two sides of a triangle is parallel to the base. 3. **Triangles upon the same base, and between the same parallels are equal to one another.** The lines joining the bisections of the sides of any quadrilateral figure, together constitute a parallelogram.... | |
| Great Britain. Committee on Education - 1855
...equal, each to each, namely, those to which the equal sides are opposite, 2. Parallelograms on the **same base and between the same parallels are equal to one another.** 3. In any triangle, if the square of one of the sides is equal to the squares of the two other sides,... | |
| Euclides - 1856
...BCD; therefore, the diameter BC divides the parallelogram into two equal parts. XXXVII. Parallelograms **upon the same base and between the same parallels are equal to one another. Let the** parallelograms ABCD, EBCF (Fig. 29) be upon the same base BC, and between the same parallels AF, BC... | |
| Cambridge univ, exam. papers - 1856
...College. WILLIAM HENRY BESAHT, MA St John's College. TUESDAY, January 6, 1857. 9... 12. 1. PARALLELOGRAMS **upon the same base, and between the same parallels, are equal to one another.** ABC is an isosceles triangle, of which A is the vertex : AB, AC, are bisected in D and E respectively... | |
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